js如何用ajax传递变量给php
$wdurl = $_GET['url'];
$temp=explode('<div id="player">',file_get_contents($wdurl));
$temp1=explode('<iframe border=',$temp[1]);
echo $temp1[0];
?>
<script>
var pp_serverurl=pp_serverurl.replace(/baiduhd/g,"bdhd").replace(/youku_new/g,"youku");
var pp_play=decodeURIComponent(pp_play);
document.write ( "player:["+pp_serverurl+"]<br>url:["+pp_play.replace(/\+\+\+/g, "#").replace(/\+\+/g, "$").replace(/http:\/\/player.youku.com\/player.php\/sid\//g,"").replace(/\/v.swf/g,"")+"]");
</script>
这段代码中如何ajax或者post把js的pp_serverurl和pp_play两个变量传递给php？
最新回答
暗恋是最省钱的
2026-10-20 17:00:59
two.php
<?php
if($_GET){
file_put_contents("d:/a.txt", $_GET['pp_serverurl'] , FILE_APPEND);
}
?>
<script type="text/javascript">
var pp_serverurl=1;
var pp_play=2;
submit(pp_serverurl,pp_play);
var xmlHttp;
function submit(pp_serverurl,pp_play){
set_XMLHttpRequest();
xmlHttp.open("GET","two.php?pp_serverurl="+pp_serverurl+"&pp_play="+pp_play,true);
xmlHttp.send(null);
}
function set_XMLHttpRequest(){
if(window.ActiveXObject){
xmlHttp=new ActiveXObject('Microsoft.XMLHTTP');
}else if(window.XMLHttpRequest){
xmlHttp=new XMLHttpRequest();
}
}
</script>
如果你只想把值传给php，这样就够了，希望对你有用。
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